Question 412.
A cord is padded over a weightless and frictionless pulley. Masses of 50 grams and 60 grams are attached to the ends of the cord. Determine the acceleration of the system and find the distance the masses will move during the third second after they are stared from rest.
Answer 412.
Let T = tension in the cord
=> 0.06 * 9.81 - T = 0.06 a
and T - 0.05 * 9.81 = 0.05 a
Adding,
0.01 * 9.81 = 0.11 a
=> a = 0.892 m/s^2
Distance travelled in the third second
= S3 - S2
= (1/2) a (3^2 - 2^2)
= (1/2) * (0.892) * 5 m
= 2.23 m.
Link to YA!
A cord is padded over a weightless and frictionless pulley. Masses of 50 grams and 60 grams are attached to the ends of the cord. Determine the acceleration of the system and find the distance the masses will move during the third second after they are stared from rest.
Answer 412.
Let T = tension in the cord
=> 0.06 * 9.81 - T = 0.06 a
and T - 0.05 * 9.81 = 0.05 a
Adding,
0.01 * 9.81 = 0.11 a
=> a = 0.892 m/s^2
Distance travelled in the third second
= S3 - S2
= (1/2) a (3^2 - 2^2)
= (1/2) * (0.892) * 5 m
= 2.23 m.
Link to YA!
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