Question 411.
A spacecraft lands on a newly discovered planet orbiting the star Antares.To measure the acceleration due to gravity on the planet,Dave ,an astronaut, drops a rock from a height of 2m. A precision timer indicates that it takes the rock 0.71s to fall to the ground.
a-Calculate the acceleration due to gravity on the new planet.
b-Find the mass of the new planet ,given that the radius of the planet is 6.05*10^6m.
c-Calculate the gravitional accelration at the location 50.0km from the surface of this planet.
Answer 411.
a)
2 = (1/2) a * (0.71)^2
=> a = 4/(0.71)^2 = 7.935 m/s^2
b)
a = GM/R^2
=> Mass, M
= aR^2/G
= (7.935) * (6.05 * 10^6)^2 / (6.67 * 10^-11) kg
= 4.35 x 10^24 kg
c)
acceleration at the height, h of 50 km
= GM/(R + h)^2
= 6.67 x 10^-11 * 4.35 x 10^24 / [(6.05 + 0.05) x 10^-6]^2 m/s^2
= 7.80 m/s^2.
Link to YA!
A spacecraft lands on a newly discovered planet orbiting the star Antares.To measure the acceleration due to gravity on the planet,Dave ,an astronaut, drops a rock from a height of 2m. A precision timer indicates that it takes the rock 0.71s to fall to the ground.
a-Calculate the acceleration due to gravity on the new planet.
b-Find the mass of the new planet ,given that the radius of the planet is 6.05*10^6m.
c-Calculate the gravitional accelration at the location 50.0km from the surface of this planet.
Answer 411.
a)
2 = (1/2) a * (0.71)^2
=> a = 4/(0.71)^2 = 7.935 m/s^2
b)
a = GM/R^2
=> Mass, M
= aR^2/G
= (7.935) * (6.05 * 10^6)^2 / (6.67 * 10^-11) kg
= 4.35 x 10^24 kg
c)
acceleration at the height, h of 50 km
= GM/(R + h)^2
= 6.67 x 10^-11 * 4.35 x 10^24 / [(6.05 + 0.05) x 10^-6]^2 m/s^2
= 7.80 m/s^2.
Link to YA!
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