Question 415.
A 4.4 m uniform pipe whose weight is 450 N is supported at each end by cords. two loads of 327N and 396 N are suspended 1.5m from the left end and 2.8m from the right end respectively. Find the tension in each cord.
Answer 415.
Let T1 and T2 be the tensions in the left and right cord respectively.
Taking moment at the right end of the rod,
T1 * 4.4 = 327 * (4.4 - 1.5) + 450 * 2.2 + 396 * 2.8
=> 4.4 T1 = 948.3 + 990 + 1108.8
=> T1 = 692.5 N.
Similarly, taking moment about the left end of the rod,
T2 * 4.4 = 450 * 2.2 + 396 * (4.4 - 2.8) + 327 * 1.5
=> 4.4 T2 = 990 + 633.6 + 490.5
=> T2 = 480.5 N
======================================
Verification:
Total upward forces
= T1 + T2 = 692.5 + 480.5 = 1173 N.
Total downward forces
= 450 + 327 + 396 = 1173 N.
Link to YA!
A 4.4 m uniform pipe whose weight is 450 N is supported at each end by cords. two loads of 327N and 396 N are suspended 1.5m from the left end and 2.8m from the right end respectively. Find the tension in each cord.
Answer 415.
Let T1 and T2 be the tensions in the left and right cord respectively.
Taking moment at the right end of the rod,
T1 * 4.4 = 327 * (4.4 - 1.5) + 450 * 2.2 + 396 * 2.8
=> 4.4 T1 = 948.3 + 990 + 1108.8
=> T1 = 692.5 N.
Similarly, taking moment about the left end of the rod,
T2 * 4.4 = 450 * 2.2 + 396 * (4.4 - 2.8) + 327 * 1.5
=> 4.4 T2 = 990 + 633.6 + 490.5
=> T2 = 480.5 N
======================================
Verification:
Total upward forces
= T1 + T2 = 692.5 + 480.5 = 1173 N.
Total downward forces
= 450 + 327 + 396 = 1173 N.
Link to YA!
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