Blog Archive

Sunday, November 20, 2011

Q.380. Centroid of a triangle.

Question 380.
Segments AD = 10, BE = 6 and CF = 24 are drawn from the vertices of triangle ABC , each perpendicular to a straight line RS, not intersecting the triangle. Points D, E and F are the intersection points of RS with the perpendiculars. If x is the length of the perpendicular segment, GH, drawn to RS from the intersection point, G, of the medians of the triangle, then find the value of x.

Answer 380.
Treat RS as x-axis.
=> y-coordinate of A, B and C are
AD=10, BE = 6 and CF = 24 respectively.
=> y-coordinate of the median G
= GH = (1/3) (10 + 6 + 24) = 40/3.
=> x = 40/3.

Link to YA!

No comments:

Post a Comment