Question 305.
Two circles of diameters 10 cm and 15 cm are placed inside a square touching each other such that one circle touches a pair of adjacent sides and the other touches the remaining pair of adjacent sides of the square. Find the perimeter of the square.
Answer 305.
Let x = diagonal of the square
Refer to the figure as under.
x
= [R + r + √2 R + √2 r]
= [5 + 7.5 + √2 (5 + 7.5)]
= 12.5 (√2 + 1)
=> length of the side
= x / √2
and perimeter
= 4x / √2
= 50 (√2 + 1) / √2
= 85.4 cm.
Link to YA!
Two circles of diameters 10 cm and 15 cm are placed inside a square touching each other such that one circle touches a pair of adjacent sides and the other touches the remaining pair of adjacent sides of the square. Find the perimeter of the square.
Answer 305.
Let x = diagonal of the square
Refer to the figure as under.
x
= [R + r + √2 R + √2 r]
= [5 + 7.5 + √2 (5 + 7.5)]
= 12.5 (√2 + 1)
=> length of the side
= x / √2
and perimeter
= 4x / √2
= 50 (√2 + 1) / √2
= 85.4 cm.
Link to YA!
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